8f^2+24f+18=0

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Solution for 8f^2+24f+18=0 equation: 



8f^2+24f+18=0

a = 8; b = 24; c = +18;
Δ = b2-4ac
Δ = 242-4·8·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{-24}{16}=-1+1/2$

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